diffusion in ptraj

From: Ioana Cozmuta <ioana.nas.nasa.gov>
Date: Mon, 7 Jul 2003 14:56:56 -0700 (PDT)


I have a question about the message posted in ptraj when doing a diffusion
calculation. It says:

      To calculated diffusion constants, calculate the slope of the
      and multiply by 10.0/6.0; this will give units of 1x10**-5 cm**2/s
      The atoms in the calculation follow: * (All atoms are selected)

This is not clear to me. As far as I know diffusion constants, D, are
calculated from Einstein's equation
MSD = 6*D*t

if log log plotted the eq above becomes
ln(MSD) = ln(6*D) + ln(t)

meaning that one should do a fit with two parameters: the ofset A0 and the
slope A1. If one reaches the diffusive regime A1 should be 1 and the
diffusion constant is calculated from the ofset (and not the slope as
written above):

D = exp(A0)/6 in units of A^2/ps
D = exp(A0)*10/6 in units of 1x10^(-5) cm^2/ps

As far as I can see from the code the data dumped in the output files are
the MSD and time.

Why is the preference towards a regular plot instead of log-log plot?

I would appreciate your comments.
Thank you,
Received on Mon Jul 07 2003 - 23:53:01 PDT
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