[AMBER] Free energy calculation

From: Sadaf Rani <sadafrani6.gmail.com>
Date: Mon, 30 Sep 2019 11:56:07 +0100

Dear Amber users
I am trying to calculate the absolute free energy of ligand but every time
I am getting an error as below:-


*At line 637 of file mdin_ctrl_dat.F90 (unit = 5, file = 'min.in
<http://min.in>')Fortran runtime error: Cannot match namelist object name ”*

My input files are as under:-

*minimization*
 &cntrl
   imin = 1, ntmin = 2,
   maxcyc = 100,
   ntpr = 20, ntwe = 20,
   ntb = 1,
   ntr = 1, restraint_wt = 5.00,
   restraintmask='!:WAT & !.H=',

   icfe = 1, ifsc = 1, clambda = 0.0, scalpha = 0.5, scbeta = 12.0,
   logdvdl = 0,
   timask1=':1', scmask1=':1',
   timask2=”, scmask2=”,
 /
 &ewald
 /

*heating*
 &cntrl
   imin = 0, nstlim = 10000, irest = 0, ntx = 1, dt = 0.002,
   nmropt = 1,
   ntt = 1, temp0 = 300.0, tempi = 5.0, tautp = 1.0,
   ntb = 1,
   ntc = 2, ntf = 1,
   ioutfm = 1, iwrap = 1,
   ntwe = 1000, ntwx = 1000, ntpr = 1000, ntwr = 5000,

   ntr = 1, restraint_wt = 5.00,
   restraintmask='!:WAT & !.H=',

   icfe = 1, ifsc = 1, clambda = 0.5, scalpha = 0.5, scbeta = 12.0,
   logdvdl = 0,
   timask1=':1', scmask1=':1',
   timask2=”, scmask2=”,
 /
 &ewald
 /

 &wt
   type='TEMP0',
   istep1 = 0, istep2 = 8000,
   value1 = 5.0, value2 = 300.0
 /

 &wt type = 'END'
 /

*pressurising*
 &cntrl
   imin = 0, nstlim = 10000, irest = 1, ntx = 5, dt = 0.002,
   ntt = 1, temp0 = 300.0, tautp = 1.0,
   ntp = 1, pres0 = 1.0, taup = 2.0,
   ntb = 2,
   ntc = 2, ntf = 1,
   ioutfm = 1, iwrap = 1,
   ntwe = 1000, ntwx = 1000, ntpr = 1000, ntwr = 5000,

   ntr = 1, restraint_wt = 5.00,
   restraintmask='!:WAT & !.H=',

   icfe = 1, ifsc = 1, clambda = 0.5, scalpha = 0.5, scbeta = 12.0,
   logdvdl = 0,
   timask1=':1', scmask1=':1',
   timask2=”, scmask2=”,
 /
 &ewald
 /


Could you please suggest me where I am doing wrong?

Thanks in advance

Sadaf
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Received on Mon Sep 30 2019 - 04:00:02 PDT
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