[AMBER] SMD for proton transfer

From: Santi Tolosa <santitolosa56.gmail.com>
Date: Tue, 14 May 2013 15:19:54 +0200

Dear Dr. Dodson

I'm building the PMF of the proton transfer of amino acids in aqueous
solution with the SMD method (steered molecular dynamics) implemented in
Amber 12 program. We obtain a final energy (associated with the neutral
structure) of - 4 kcal/mol, more stable than the initial energy (associated
to the neutral structure), which does not seem logical. For them I am using
the files:

Mdin0

Glycine: qmmm equilibration MD

 &cntrl

  imin = 0,

  irest = 0,

  ntx = 1,

  ntb = 1,

  cut = 5.0,

  tempi = 300.0,

  temp0 = 300.0,

  ntt = 1,

  gamma_ln = 0.0,

  ntf = 2, ntc = 2, tol = 0.00001,

  dt = 0.0005,

  ntpr = 50, ntwr=100, ntwx = 100,

  nstlim = 100000,

  ifqnt = 1,

  nmropt = 1,

  ibelly=1, bellymask=':WAT',

 /

 &qmmm

  qmmask=':1',

  qmcharge=0,

  qm_theory='DFTB',

  qmshake=0,

  writepdb=1,

 /

 /

 &wt type='DUMPFREQ', istep1 = 10,

 /

 &wt type='END',

 /

DISANG=dist.RST

DUMPAVE=dist_vs_t

LISTIN=POUT

LISTOUT=POUT



 Mdin1

Glycie: NCSU steered MD: LCOD rxn coord

 &cntrl

  imin = 0,

  irest = 1,

  ntx = 5,

  ntb = 1,

  cut = 5.0,

  tempi = 300.0,

  temp0 = 300.0,

  ntt = 1,

  gamma_ln = 0.0,

  ntf = 2, ntc = 2, tol = 0.00001,

  dt = 0.001,

  ntpr = 100, ntwr=100, ntwx = 1000,

  nstlim = 50000,

  ifqnt = 1,

 /

 &qmmm

  qmmask=':1',

  qmcharge=0,

  qm_theory='DFTB',

  qmshake=0,

  writepdb=1,

 /



ncsu_smd



   output_file = 'smd.txt'

   output_freq = 500



   variable

   type = LCOD ! Linear Combination of Distance

   i = (9,10,1,10)

   r = (1.0,-1.0)

   path = (1.42,-1.25) path_mode = LINES

   harm = (1000.0)

   end variable



end ncsu_smd


smd.txt

#

# MD time (ps), CV, handle_position, spring_constant, work

#



    50.0000 1.49452542 1.42000000 1000.00000000
0.00000000


     52.5000 1.09928957 1.15300000 1000.00000000
0.73671660



    55.0000 0.82355211 0.88600000 1000.00000000
1.45414492



   57.5000 0.66830655 0.61900000 1000.00000000
2.73445986



   60.0000 0.41748331 0.35200000 1000.00000000
5.04733323



   62.5000 0.01930706 0.08500000 1000.00000000
6.98244045



    65.0000 -0.13774148 -0.18200000 1000.00000000
6.30370813


     67.5000 -0.43998671 -0.44900000 1000.00000000
3.24075496


     70.0000 -0.67032144 -0.71600000 1000.00000000
 -0.81911976


     72.5000 -1.06095224 -0.98300000 1000.00000000
 -3.44306421

#

#

 <> total work done: -4.2166710649

#



Can you help me to solve the problem?
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Received on Tue May 14 2013 - 06:30:02 PDT
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